dov6891 2017-03-21 15:24
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将所有内容匹配到精确div中的最后一个确切字符串（php）

I want to match the address of a property on realty server. Lets say the div containing address is named <div class="title"> and the address is located in the last <h2> section like this: 

<body>
  <div class="price">
    <h2>
      h2
    </h2>
  </div>      
  <div class="title">
    <abcd>
      abcd
    </abcd>
    <efg>
      efg
    </efg>
    <h2>
      adress
    </h2>
 </div>
</body>

Is there a possible way to capture an address by only one regex, even if it will be in some captured group?

My not working solution is:

regex="/<div class="title">everything_except_<h2>*([^<]*)/";
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1条回答 默认 最新

  • dongshou2024 2017-03-21 15:31
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    Try this regex:

    <div class="title">(?:.(?!<\/div>))*<h2>([^<]*)

    The main point here is to make .* after <div class="title"> greedy but match only until </div> is found. So the regex limits the . with only those occurrences that are not followed by </div> (which gives us (?:.(?!<\/div>))* as a result).

    Demo: https://regex101.com/r/2EGXue/1

    Update:

    If nested divs may occur but only one level of nesting is possible and the required <h2>...</h2> is not within any of those divs (as it happens in the provided data sample), the greedily matching pattern (.(?!<\/div>)) should be extended to match either "not <div ...>...</div>" (which is <div.*?<\/div>) or just "not </div>" (.(?!<\/div>)):

    <div class="title">(?:<div.*?<\/div>|.(?!<\/div>))*<h2>([^<]*)

    Demo: https://regex101.com/r/IGLhBZ/1

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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