doushan9415 2016-12-30 00:54
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如何解决错误:在laravel 5.3中调用未定义的函数App \ Http \ Controllers \ JSON_EXTRACT()?

For example, I have a column named json in table A

Json column contains json data like this :

record 1 : {"dept_code": "012", "unit_code": "22"}
record 2 : {"dept_code": "013", "unit_code": "23"}
etc

I want to take the data records with json column that contain dept_code = 012

I try like this :

$id = "012";
$data = \DB::table('table_A')
           ->select('*')
           ->where(JSON_EXTRACT('json', "$.dept_code"), '=', '"'.$id.'"')
           ->get();

There exist error like this :

Call to undefined function App\Http\Controllers\JSON_EXTRACT()

How can I resolve that?

  • 写回答

1条回答 默认 最新

  • dongxi7704 2016-12-30 01:12
    关注

    You can use laravel's JSON where clauses. E.g.

    $id = "012";
    $data = DB::table('table_A')
               ->where('json->dept_code', $id)
               ->get();
    

    This works in Postgres and MySQL(since 5.7.8)

    Query Builder Where Clauses

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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