dongpiao1983 2018-06-11 11:32
浏览 152
已采纳

显示错误消息时不应重新加载

I have created a login page which is working fine but the issue I'm facing is when I enter an invalid username, name or password.

It should show "invalid username or password" without loading the page, that is what AJAX is used right? But instead, when I enter an invalid username name or password, it is showing an error that the username name or password is invalid by loading the page which is not acceptable in case of AJAX.

Can anyone help me fix this issue that the error message should be shown without reloading of the page?

login.php:

<?php 

    session_start(); 
    $mysqli  = mysqli_connect("localhost","root","","ajax1");
    if (isset($_SESSION['id'])){
        header('location:welcome.php');
    }

?>
<!DOCTYPE HTML>  
<html>

<head>
    <title> login script with ajax</title>
    <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
</head>

<body style="background-color:#b3ffff">

    <div style="padding-left:500px ; padding-top:200px">

        Username:   <input id="username" type="text" name="username" placeholder="username"><br><br>
        Password:   <input id="password" type="password" name="password" placeholder="Password"><br><br>
                    <input id="submit" name="submit" type="button" value="Log In">
                    <p style="color:black">Havent Registered Yet? <a href="index.php">Register</a>.</p><br><br>
                    <div id="display" style="color:red"></div>

        <script>
            $(document).ready(function(){
                $("#submit").click(function(){
                    var username = $("#username").val();
                    var password = $("#password").val();

                    var datastring = 'username=' + username + '&password=' + password;

                    if(username=='' || password==''){
                        $("#display").html("Please Enter All The Fields");
                    }
                    else{
                        $.ajax({
                        type: "POST",
                        url: "success.php",
                        data: datastring,
                        cache: false,
                        success: function(result){
                                $("#display").html(result);
                                window.location = "welcome.php";
                            }
                        });
                    }
                    return false;
                });
            });
        </script>
    </div>

</body>
</html>

success.php:

<?php

    $mysqli  = mysqli_connect("localhost","root","","ajax1");
    session_start();

    if (isset($_SESSION['id'])){
        header('location:welcome.php');
    }

    $myusername = mysqli_real_escape_string($mysqli,$_POST['username']);
    $mypassword = mysqli_real_escape_string($mysqli,$_POST['password']); 

    $sql = "SELECT * FROM users WHERE username = '$myusername'";
    $result = mysqli_query($mysqli,$sql);
    $row = mysqli_fetch_array($result);
    $hashed_password=$row['password'];

    if(password_verify($mypassword, $hashed_password)) {
        $_SESSION['login_user'] = $myusername;
        $_SESSION['id']=$row['userid'];
        echo'Successfully Registered';
    exit();
    }    
    else 
    {
    echo'Invalid username or password';
    }
?>

welcome.php:

<?php
    session_start();
    if (!isset($_SESSION['id'])) {
        header('location:login.php');
    }
?>

<!DOCTYPE html>
<html>

<head>

    <title>Bootstrap Example</title>
    <meta charset="utf-8">
    <meta name="viewport" content="width=device-width, initial-scale=1">
    <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
    <script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>

</head>

<body>

    <div style="Padding-left:200px; padding-top:100px">
            <?php
                $mysqli  = mysqli_connect("localhost","root","","ajax1");
                $query=mysqli_query($mysqli,"select * from `users` where userid='".$_SESSION['id']."'");
                $row=mysqli_fetch_array($query);
                echo 'Welcome - '.$row['username'];
            ?>

            <br><br>
                <a href="logout.php">Logout</a>
            <br><br>

            <div class="panel panel-primary" style="width:56%">

                <div class="panel-heading text-center">STUDENT'S DETAILS</div>

            </div>  


        <div class="container text-center">

            <?php

                $mysqli  = mysqli_connect("localhost","root","","ajax1");

                if (!isset($_POST["happy"])) {  
                    $result = mysqli_query($mysqli, "SELECT * FROM users");
                } else {
                            $search = mysqli_real_escape_string($mysqli, $_POST["happy"]);
                            $result = mysqli_query($mysqli, "SELECT * FROM users where department like '%$search%'");
                        } if(mysqli_num_rows($result) > 0) {
                    echo "<table border='1' class='text-center' >
                    <tr>

                        <th>USER_ID</th>
                        <th>USERNAME</th>
                        <th>E-MAIL</th>
                        <th>NAME</th>
                        <th>AGE</th>
                        <th>DATE_OF_BIRTH</th>
                        <th>DEPARTMENT</th>

                    </tr>";

                    while($row = mysqli_fetch_array($result))
                    {
                    echo "<tr>";
                        echo "<td>" . $row['userid'] . "</td>";
                        echo "<td>" . $row['username'] . "</td>";
                        echo "<td>" . $row['email'] . "</td>";
                        echo "<td>" . $row['name'] . "</td>";
                        echo "<td>" . $row['age'] . "</td>";
                        echo "<td>" . $row['date_of_birth'] . "</td>";
                        echo "<td>" . $row['department'] . "</td>";

                    echo "</tr>";
                    }
                echo "</table>";
                        }
                        else{
                            echo 'Sorry no record found';
                            }

            ?>

        </div>


        <div class="container form-group">
            <br><br>
            <form method="post">
                <label class="control-label" style="color:blue">Select :</label>

                <select name="happy" style="margin-left:14px; color:black;">
                                <option disabled selected value> -- select an option -- </option>
                                <option value="EE">Electrical & Electronics</option>
                                <option value="EC">Electronics & Communication</option>
                                <option value="ME">Mechanical</option>
                                <option value="CS">Computer Science</option>
                                <option value="CV">Civil</option>
                                <option value="IS">Information Science</option> 
                </select>
                <input type="submit" value="submit">
            </form>
        </div>

    </div>             
</body>
</html>
  • 写回答

1条回答 默认 最新

  • dongmei9961 2018-06-11 11:37
    关注

    Get JSON Response like following:

    {success: true} or {success: false}
    

    and check it ajax success

    if(result.success == true) {
     window.location = 'welcome.php';
    }
    

    OR in your code

    if(result.indexOf('Successfully') > -1) {
     window.location = 'welcome.php';
    }
    

    Edit: Repo

    $.ajax({
     type: "POST",
     url: "success.php",
     data: datastring,
     cache: false,
     success: function(result){
      $("#display").html(result);
      if(result.indexOf('Successfully') > -1) {
       window.location = "welcome.php";
      }
     }
    });
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 安卓adb backup备份应用数据失败
  • ¥15 eclipse运行项目时遇到的问题
  • ¥15 关于#c##的问题:最近需要用CAT工具Trados进行一些开发
  • ¥15 南大pa1 小游戏没有界面,并且报了如下错误,尝试过换显卡驱动,但是好像不行
  • ¥15 没有证书,nginx怎么反向代理到只能接受https的公网网站
  • ¥50 成都蓉城足球俱乐部小程序抢票
  • ¥15 yolov7训练自己的数据集
  • ¥15 esp8266与51单片机连接问题(标签-单片机|关键词-串口)(相关搜索:51单片机|单片机|测试代码)
  • ¥15 电力市场出清matlab yalmip kkt 双层优化问题
  • ¥30 ros小车路径规划实现不了,如何解决?(操作系统-ubuntu)