dongque1958 2018-01-31 16:49
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如何将更多参数传递给该函数?

I have this function:

function mobio_checkcode($servID, $code, $debug=0) {

$res_lines = file("http://www.mobio.bg/code/checkcode.php?servID=$servID&code=$code");

$ret = 0;
if($res_lines) {

    if(strstr("PAYBG=OK", $res_lines[0])) {
        $ret = 1;
    }else{
        if($debug)
            echo $line."
";
    }
}else{
    if($debug)
        echo "Unable to connect to mobio.bg server.
";
    $ret = 0;
}

return $ret;
}

And here how i use it:

if(mobio_checkcode($servID, $code, 0) == 1) {
 echo "Code is valid!!";
}


$code = $_REQUEST['code'];
$servID = 29;
$post = $_REQUEST['post'];

Here i have form! In this form u enter code and display is valid or no so i want to pass more $code like

$code1 = $_REQUEST['code1'];
$code2 = $_REQUEST['code2'];
$code3 = $_REQUEST['code3'];

I want to pass more variables to function how it will be done.. Please help me thank u <3

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2条回答 默认 最新

  • dsfo22654 2018-07-13 14:03
    关注

    Just pass all of variables as array like

    $array = ['servID'=>29,'code'=>XXXX];
    
    function checkcode($array) {
    //Do stuff
    $array['servID']
    $array['code']
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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