doushui5587 2016-07-11 08:42
浏览 71

PHP在下一页中获取提交按钮的ID

if ($result->num_rows > 0) 
{
    while($row = $result->fetch_assoc()) 
    {

         echo "<form name=frm  action=edit.php method=POST";
        echo "<tr>";
        echo "<td>" . $row["Sl_no"]. "</td>";
        echo "<td> " . $row["nam"]. "</td>";
        echo "<td> " . $row["age"]. " </td>";
        echo "<td> " . $row["dob"]. "</td>";
        echo "<td> " . $row["gender"]. " </td>";
        echo "<td> " . $row["married"]. " </td>";
        echo "<td> " . $row["temp_addr"]. " </td>";
        echo "<td> " . $row["fix_addrs"]. " </td>";
        echo "<td> " . $row["email"]. " </td>";
        echo "<td> " . $row["phone"]. " </td>";
        echo "<td> " . $row["mother_tounge"]. " </td>";
        echo "<td> " . $row["nationality"]. " </td>";
        echo "<td> " . $row["clg"]. " </td>";
        echo "<td> " . $row["sem"]. " </td>";
        echo "<td> " . $row["grad"]. " </td>";
        echo "<td> " . $row["qual"]. " </td>";
        echo "<td> " . $row["branch"]. " </td>";
       echo "<td> <input type=submit name =" .$row["Sl_no"]. " value =Edit  ><input type=button id=d".$row["Sl_no"]." value=Delete />";
        echo "</tr>";
        echo"</form>";
    }

I am using this code and in each field there will be a random named submit will generate. I want to transfer the name of the button to next page or pass the value of first tag help me.

  • 写回答

3条回答 默认 最新

  • douleng0794 2016-07-11 08:46
    关注

    On the next page you can use $_POST['key']; or $_GET['key']. That will give you access to your value from the key.

    评论

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