PHP：从gunzip写入文件

Question

I'm getting a gzipped File from an FTP Server that contains an xml. I want to gunzip it und write the xml as a file.

This is the code I'm using right now:

ftp_get($ftpCon, __DIR__."/../files/data.gz", $val, FTP_BINARY);

$srcName = __DIR__."/../files/data.gz";
$dstName = __DIR__."/../files/stuff.xml";
$command = 'gunzip -c '.$srcName.' > '.$dstName;
$escapedCommand = escapeshellcmd($command);

system($escapedCommand);

But the XML File will be printed out on the console and not written into a file. How can I write the data from the zipped file into an XML file?

Answer 1

The problem lies in your use of escapeshellcmd. If you look at this example, you'll see that your escaped command looks like this:

gunzip -c from/data.gz \> to/stuff.xml

But you don't want the > to be escaped. Since you have full control over the rest of the command, try escaping only the filenames (you don't have to if they're hard-coded like in your example).