如何在PHP中以适当的json格式转换包含多个json数据的字符串？

Question

How can I convert this string:

{"id":"tag:search.twitter.com,2005:1"}{"id":"tag:search.twitter.com,2005:2"}
{"id":"tag:search.twitter.com,2005:3"}{"id":"tag:search.twitter.com,2005:4"}

Into this JSON format:

[
    {"id":"tag:search.twitter.com,2005:1"},
    {"id":"tag:search.twitter.com,2005:2"},
    {"id":"tag:search.twitter.com,2005:3"},
    {"id":"tag:search.twitter.com,2005:4"}
]

Answer 1

Assuming that your string is composed of valid JSON object put together without any delimiter, you can do the following:

1. Split the string with }{ as delimiter
2. Loop over each item in the resulting array and add the missing parts
3. Merge the array into one string with a , as delimiter
4. Add the JSON array marks before and after the string

Example (with $input as the input string):

$chunks = explode('}{', $input);
$n = count($chunks);
for($i = 0; $i < $n; $i++) {
    if($i == 0) {
        $chunks[$i] = $chunks[$i].'}';
    } else if($i == $n - 1) {
        $chunks[$i] = '{'.$chunks[$i];
    } else {
        $chunks[$i] = '{'.$chunks[$i].'}';
    }
}
$output = '['.implode(',', $chunks).']';

Note that it will work on imbricated structures, but will miserably fail if you have a }{ in the text. But it is unlikely.

EDIT: One simple way of checking if the current chunk is a wrong cut could be by checking is the next chunk start with a ", because JSON object's attributes are always quoted. If not, then you can merge the current and next chunk and repeat until finding the right character.