在函数内使用包含文件的变量

Question

I've got a problem.

I've got 3 files, which'd be:

apikey.php

<?php

    $apikey = 'xxxxxxxx';

?>

core.php

<?php

    include 'apikey.php';

    /* some other stuff here */

?>

login.php

<?php

    include 'core.php';

    function GetUserData($id) {
        global $apikey;

        /* some other stuff here */

        return $apikey; // <- returning NULL
    }

?>

So, as the comment says, $apikey is being returned as NULL.

But using it outside the function GetUserData it works as it should.

Any ideas?

Answer 1

Try to declare the global in apikey.php and then define it.

global $apikey;
$apikey = 'xxxx';

Nevertheless is using a global what you need? Think about passing it as a parameter.