PHP - 获取在另一个PHP文件中回显的XML文件，然后将回显的XML输出保存到服务器

Question

I have an PHP file - called xml_generate.php - that creates a DOM object and echoes it at the very end.

Lets say it looks like this:

header("Content-type: text/xml"); 

$dom = new DOMDocument('1.0');
$node = $dom->createElement('foo');
$root = $dom->appendChild($node);

$node = $dom->createElement('bar');
$new_node = $root->appendChild($node);

echo $dom->saveXML();

I'm accessing this file from jQuery and displaying the content on the client-side. The actual xml_generate.php creates the DOM dynamically from a database.

However, I want to have a PHP file that will create a backup of the XML generated by generate_xml.php and save it to the server.

So, I need to somehow access that XML document (the one that is dynamically created in xml_generate.php).

I've tried a a few different functions to get the XML from xml_generate.php, for instance:

$xml = http_get('xml_generate.php');,

$xml = file_get_contents('xml_generate.php');

as well as just including the first file (include('xml_generate.php'), then just trying to access the $dom variable in that file).

but I can't seem to get it right. Any ideas on the best approach to do this?

Answer 1

You could use Output Buffering, which will buffer any data sent to the output stream, and then retrieve that after including your script:

ob_start();
include "xml_generate.php";
$xml = ob_get_contents();
ob_end_clean();

Make sure to catch errors @"xml_generate.php" though, or these will be buffered as well and you'll end up with an invalid xml backup.