编写高级正则表达式

Question

Firstly sorry for my bad English. I'm newbie with regex. I'm trying to make auto translation. For example I have a text like:

/begin CHARACTERISTIC

    AccPed_trqEngLow_MAP
    "Kennfeld für AWD"
    MAP
    0x801B425C
    Map_Xs16Ys16Ws16
    1500.000
    Trq
    -500.0000
    1000.000

    FORMAT "%8.3"
    EXTENDED_LIMITS -3276.800 3276.700


    /begin AXIS_DESCR

        STD_AXIS
        Epm_nEng
        EngN
        16
        0.00
        10000.00

        FORMAT "%8.2"
        EXTENDED_LIMITS -16384.00 16383.50
        DEPOSIT ABSOLUTE

    /end AXIS_DESCR

    /begin AXIS_DESCR

        STD_AXIS
        AccPed_rAPP
        Prc
        8
        0.00
        100.0000

        FORMAT "%8.4"
        EXTENDED_LIMITS -400.0000 399.9878
        DEPOSIT ABSOLUTE

    /end AXIS_DESCR

/end CHARACTERISTIC

I need to select all strings in "" like "Kennfeld für AWD", but do not select where starts with % ("%8.3") Is it possible at least? Thanks in advance.. P.S string may contain quotation marks inside, like "Hello "world" !" It is very difficult for me.

Answer 1

/\"([^%].*)\"/g matches all strings in quotes that don't start with a % symbol.

In javascript (es6) it would be:

const example = `
/begin CHARACTERISTIC

    AccPed_trqEngLow_MAP
    "Kennfeld für AWD"
    MAP
    0x801B425C
    Map_Xs16Ys16Ws16
    1500.000
    Trq
    -500.0000
    1000.000

    FORMAT "%8.3"
    EXTENDED_LIMITS -3276.800 3276.700

/end CHARACTERISTIC
`

let re =  /\"([^%].*)\"/g;
let results = example.match(re);

console.log(results)