dourang8305 2018-10-10 12:47
浏览 442

laravel join:如何根据我的条件连接表并从同一个连接中提取各种数据?

This is what I have done so far.

DB::table('products')
 ->leftjoin('inventories', 'inventories.product_id', 'products.id')
 })
 ->leftjoin('order_items as purchase_oi', function($query){
 $query->on('purchase_oi.inventory_id', 'inventories.id');
  $query->on('purchase_oi.status','!=', \DB::raw('"cancelled"'));
                        })                       
 ->select(DB::raw('sum(inventories.quantity)as qty'),
 DB::raw('count(purchase_oi.inventory_id) as purchases'),                            
  'products.id as pid', 'products.*')                          
  ->where('products.is_deleted', 0)
  ->where('inventories.is_deleted',0)
  ->groupBy('inventories.product_id')                  
  ->get();

order_items table contains the status in

enum('shipped','return''cancelled');

This issue is here on the join with order_items table. Currently, I'm just getting the data which is not equal to cancelled but I want to get the order_items data which are returned and the order_items data which are cancelled. i.e get me the purchases,cancelled and return count from order_items table. Expected output is:

0=>purchases = 4,
   returns = 10,
   cancelled = 2
  • 写回答

1条回答 默认 最新

  • douguangxiang0363 2018-10-10 13:41
    关注

    I think the problem is your groupBy(). If you have the following query:

    SELECT COUNT(*) AS count FROM table GROUP BY id
    

    You don't end up with

    +-------+
    | count |
    +-------+
    | 5     |
    +-------+
    

    Instead you end up with:

    +-------+
    | count |
    +-------+
    | 1     |
    +-------+
    | 1     |
    +-------+
    | 1     |
    +-------+
    | 1     |
    +-------+
    | 1     |
    +-------+
    

    The count of all items per grouping.

    Try this:

    \DB::enableQueryLog();
    \DB::flushQueryLog();
    
    //Execute your query
    
    $queries = /DB::getQueryLog();
    /DB::disableQueryLog();
    /DB::flushQueryLog();
    
    $queries = collect($queries)->map(function (array $query) {
        return array_only($query, ['query', 'bindings']);
    })->toArray();
    
    dd($queries);
    

    This should tell you exactly what SQL is being executed.

    评论

报告相同问题?

悬赏问题

  • ¥15 file converter 转换格式失败 报错 Error marking filters as finished,如何解决?
  • ¥15 ubuntu系统下挂载磁盘上执行./提示权限不够
  • ¥15 Arcgis相交分析无法绘制一个或多个图形
  • ¥15 关于#r语言#的问题:差异分析前数据准备,报错Error in data[, sampleName1] : subscript out of bounds请问怎么解决呀以下是全部代码:
  • ¥15 seatunnel-web使用SQL组件时候后台报错,无法找到表格
  • ¥15 fpga自动售货机数码管(相关搜索:数字时钟)
  • ¥15 用前端向数据库插入数据,通过debug发现数据能走到后端,但是放行之后就会提示错误
  • ¥30 3天&7天&&15天&销量如何统计同一行
  • ¥30 帮我写一段可以读取LD2450数据并计算距离的Arduino代码
  • ¥15 飞机曲面部件如机翼,壁板等具体的孔位模型