dongtao5055 2017-02-22 04:27
浏览 192
已采纳

显示[object Object]数据的值

I got data from third party plugin and I just got [object Object] in javascript. I want to pass it on PHP and show all the values on that [object Object]. How could I to do that ? I already pass it to PHP through GET

I got this [object Object] from this part.

widget.createButton()
    .attr('title', "Save chart")
    .on('click', function (e) {
    widget.save(function(data) {
        window.location.href = "temp.php?var=" + data;
    })
})
.append($('<span>save chart</span>'));

This is my PHP code.

<?php

$var = $_GET['var'];

var_dump($var);
exit();

?>

if I do var_dump it still get [object Object] but I want to get the values of that [object Object].

  • 写回答

1条回答 默认 最新

  • drn1008 2017-02-22 04:32
    关注

    Your object is being converted to a string. Try this in a browser console to see.

    var a = {}
    a.toString() // this will give you [object Object]
    

    In your code at this step:

    window.location.href = "temp.php?var=" + data;
    

    you are converting data from object to string. You need to do this

    window.location.href = "temp.php?var=" + JSON.stringify(data);
    

    and on PHP part of the code, you will now receive it as string, so you need to do this:

    $var = var_dump(json_decode($_GET['var']));
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥20 wireshark抓不到vlan
  • ¥20 关于#stm32#的问题:需要指导自动酸碱滴定仪的原理图程序代码及仿真
  • ¥20 设计一款异域新娘的视频相亲软件需要哪些技术支持
  • ¥15 stata安慰剂检验作图但是真实值不出现在图上
  • ¥15 c程序不知道为什么得不到结果
  • ¥40 复杂的限制性的商函数处理
  • ¥15 程序不包含适用于入口点的静态Main方法
  • ¥15 素材场景中光线烘焙后灯光失效
  • ¥15 请教一下各位,为什么我这个没有实现模拟点击
  • ¥15 执行 virtuoso 命令后,界面没有,cadence 启动不起来