php写一个onkeyup =函数

Question

I am writing a php script which generates html with a javascript onkeyup event, as such:

// generate the function text
            $fn_text = "checkContentQuizAnswer(\"#".$var_name."\",\"".$equation_solutions_array[0][0]."\",\"{'incorrect_values':[";     
                for($r=1;$r<count($equation_solutions_array);$r++) {
                    // THIS ISNT WORKING CORRECTLY, NEED A BETTER WAY TO PASS INCORRECT INFO
                    $fn_text .= "{'equation':'".$equation_solutions_array[$r][0]."','message':'".$equation_solutions_array[$r][1]."'}";
                    if(($r+1)<count($equation_solutions_array)) {
                        $fn_text .= ",";
                    }
                }
            $fn_text .= "]}\")";

However this isnt working... the code it generates looks something like this:

onkeyup="checkContentQuizAnswer("#theonlyvariable","27.62*5","{'incorrect_values':[{'equation':'27.62+5','message':'you added 5'},{'equation':'27.62-5','message':'you subtracted 5'}]}")" 

however, it hasn't been working... the errors have included complaints about missing }'s, MathJax (an eval() style library) is undefined.

Im sure that it is how I am parsing the onkeyup part of the tag but i cant get the combination/syntax correct.

Can anybody see a glaring problem? :S

Thanks Alex

Answer 1

Although you are escaping the quotes in the PHP file, the quotes in the javascript parser are not being escaped. Change the quotes inside the onKeyUp to single quotes to fix this. You will also need to escape the quotes in the JSON as well - the json_encode() function can help with that. You need to output something like:

onkeyup="checkContentQuizAnswer('#theonlyvariable','27.62*5','{\'incorrect_values\':[{\'equation\':\'27.62+5\',\'message\':\'you added 5\'},{\'equation\':\'27.62-5\',\'message\':\'you subtracted 5\'}]}')"