dpj96988 2015-12-07 03:28
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出于某种未知原因的PHP语法错误[重复]

This question already has an answer here:

Recently started to fix up some code on a old project, however i'm abit rusty and can't for the life of me see whats wrong with this code.. as far as I can see it looked fine but at 3.25am anything can be wrong!

The Error:

PHP Parse error:  syntax error, unexpected 'value' (T_STRING), expecting ',' or ';'

The Code:

    <?php
if ($post_rank == 0) {
    echo '<option value="0" selected="selected">0</option>';
} else if ($post_rank == 1) {
    echo '<option value="1" selected="selected">1</option>';
} else if ($post_rank == 2) {
    echo '<option value="1" selected="selected" >2</option>';
} else if ($post_rank == 3) {
    echo '<option value="1" selected="selected">3</option>';
} else if ($post_rank == 4) {
    echo '<option value="1" selected="selected">4</option>';
} else if ($post_rank == 5) {
    echo '<option value="1" selected="selected">5</option>';
} else if ($post_rank == 6) {
    echo '<option value="1" selected="selected">6</option>';
} else if ($post_rank == 7) {
    echo '<option value="1" selected="selected">7</option>';
} else if ($post_rank == 8) {
    echo '<option value="1" selected="selected">8</option>';
} else if ($post_rank == 9) {
    echo '<option value="1" selected="selected">9</option>';
} else if ($post_rank == 10) {
    echo '<option value="1" selected="selected">10</option>';
} else if ($post_rank == 11) {
    echo '<option value="1" selected="selected">11</option>';
} else if ($post_rank == 12) {
    echo '<option value="1" selected="selected">12</option>';
} else if ($post_rank == 13) {
    echo '<option value="1" selected="selected">13</option>';
} else if ($post_rank == 14) {
    echo '<option value="1" selected="selected">14</option>';
} else if ($post_rank == 15) {
    echo '<option value="1" selected="selected">15</option>';
}
?>
</div>
  • 写回答

1条回答 默认 最新

  • douzhen5158 2015-12-07 03:34
    关注

    Here is the issue,

    echo '<option value='0' selected="selected">0</option>';
    

    It should be

    echo '<option value="0" selected="selected">0</option>';
                        ^ double quotes.
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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