使用php获取下一个第15天和/或第30天的日期？

Question

I require to get the dates of the upcoming 15th and 30ths of the next months as for the current date. (If February is within range it must be 28/29th of course).

Can I do this using mktime/strtotime or maybe using another method?

I got this but of course this is for only get the last day of this and next month. I need the upcoming 15ths and 30ths instead.

$cuota1 = date('t-m-Y', strtotime('+15 days'));
    return $cuota1;

$cuota2 = date('t-m-Y', strtotime('+30 days'));
    return $cuota2;

$cuota3 = date('t-m-Y', strtotime('+45 days'));
    return $cuota3;

Thanks in advance.

Answer 1

Hope I've got your idea right, and may be this solution is quite long, but looks like it's bullet-proof:

$numOfDays = date('t', $todayStamp);
$base = strtotime('+'.$numOfDays.' days', strtotime(date('Y-m-01', $todayStamp)));
$day15 = date('Y-m-15', $base);
$day30 = date('Y-m-'.min(date('t', $base), 30), $base);

where $todayStamp is generally the value of time(), but for debug purposes it can be strtotime() of an arbitrary date. For example, let's take "difficult" case of the next leap year:

$today = '2016-01-30';
$todayStamp = strtotime($today);
$numOfDays = date('t', $todayStamp);
$base = strtotime('+'.$numOfDays.' days', strtotime(date('Y-m-01', $todayStamp)));
$day15 = date('Y-m-15', $base);
$day30 = date('Y-m-'.min(date('t', $base), 30), $base);
var_dump($day15);
var_dump($day30);

The output is

string(10) "2016-02-15"
string(10) "2016-02-29"

and for 2016-02-29 the output will be

string(10) "2016-03-15"
string(10) "2016-03-30"