doufu9836 2015-05-16 07:21
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从存储在另一个动态变量中的日期中减去动态值

I need to subtract a number of days from a date which is stored in a dynamic variable '$workdate' .

The number of days to be subtracted from the date is also generating dynamically.

$workdate=date('d/m/y', strtotime($wdate)); //$wdate is a date selected from date picker and passed from previous page.

I have a variable named '$deduc' whose value is dynamically generating. suppose $deduc=2 now I need to do:

$workdate-$deduc=?

$workdate=date('d/m/y', strtotime($wdate));

while($some_value=0)
{
  $deduc=$deduc+1;
  $some_value--;

}

now I need to subtract $deduc no. of days from $workdate. Please do help.

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  • dongsheng4679 2015-05-16 07:31
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    Just create a DateTime object with DateTime::createFromFormat() and modify() your date, e.g.

    $date = DateTime::createFromFormat("d/m/y", $workdate);
    echo $date->modify("- $deduc days")->format('Y-m-d');
    

    <kbd>Demo</kbd>

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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