如何在以下场景中仅从整个<img>标签获取图像URL？

Question

I've an associative array titled $data as follows:

Array
(
    [0] => Array
        (
[student_image] => <img src="http://34.144.40.142/file/pic/photo/2015/02/02ff1a23db112db834b8f41748242bcb_240.png"  alt=""  width="180"  height="160"  class="photo_holder" />
)

    [1] => Array
        (
[student_image] => <img src="http://34.144.40.142/theme/frontend/foxplus/style/default/image/document/docx.png"  alt="" />
)
[2] => Array
        (
 [student_image] => <img src="http://34.144.40.142/file/pic/photo/2015/02/da46580276da5c3a31b75e8b31d35ddf_240.png"  alt=""  width="180"  height="160"  class="photo_holder" />
)
)

The actual array is very huge, here I've put in only the necessary data from array. Now what I want is for every element of the array the key [student_image] I should get only the URL of the image, no imag tag and any other data. In short I want following output of above array:

Array
(
    [0] => Array
        (
[student_image] => http://34.144.40.142/file/pic/photo/2015/02/02ff1a23db112db834b8f41748242bcb_240.png
)

    [1] => Array
        (
[student_image] => http://34.144.40.142/theme/frontend/foxplus/style/default/image/document/docx.png"
)
[2] => Array
        (
 [student_image] => http://34.144.40.142/file/pic/photo/2015/02/da46580276da5c3a31b75e8b31d35ddf_240.png
)
)

How should I achieve this in best possible and optimum way for all the elements of an array $data?

Thanks in advance.

Answer 1

try something like this:

   //$data is your array
    $data = array_map(function($elem){
       //$elem is each elemet  of you array
       return array('student_image' => preg_replace('/<img\ssrc="([^"]+)".+$/','$1',$elem['student_image']));
    },$data);