I have site running Jquery, Ajax, PHP, and an HTML form. It uses two pages.
Pages...
Example.php & Processexample.php
When you click the edit button on example.php a form pops up in the NyroModal window posting to Processexample.php and allows you to edit customer data that's posted using Ajax.
After user clicks save on Porcessexample.php a SQL update is made and a success message is posted back to the Modal Box (end-user).
Here are the issues...
- I can't get the NyroModal window to close after (data) success is called on processexample.php. I tried setting the Timeout in JQ/Javascript below but error occurs.
setTimeout("$.nyroModal.close()", 4000);
- How do i get example.php page to display updated data automatically, or have the page reload after #send button is clicked and success is displayed in modal window.
HTML Form Code on processexample.php
<form id="AjaxForm" name="AjaxForm" action="#" method="post">
<input name="submitform" type="hidden" value="1"
<button id="send">Save Client</button>
JS Code on processexample.php --> See bold text in code where issue is.
$(document).ready(function() {
$("#AjaxForm").submit(function() { return false; });
$("#send").on("click", function(e){
var idval = $("#client").val();
var calval = $("#view").val();
var emailval = $("#customer_email").val();
var nameval = $("#customer_name").val();
var phoneval = $("#customer_phone").val();
var msgval = $("#customer_note").val();
var msglen = msgval.length;
var mailvalid = validateEmail(emailval);
if(mailvalid == true && msglen >= 4) {
// if both validate we attempt to send the e-mail
// first we hide the submit btn so the user doesnt click twice
$("#send").replaceWith("<em>sending...</em>");
$.ajax({
type: 'POST',
url: 'saveclient.php',
data: $("#AjaxForm").serialize(),
success: function(data) {
if(data == "true") {
$("#AjaxForm").fadeOut("fast", function(){
$(this).before("<p><strong>Success! Your information has been updated.</strong></p>");
**setTimeout("$.nyroModal.close()", 4000);**
});
}
}
});
}
});
});
</script>