dsd119120 2012-06-11 10:14
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json jquery发帖请求

<script type="text/javascript">
    $(document).ready(function() {
        $("a").click(function() {

            var content = $('#content').html();

            var data = {"content":content};


            $.ajax({
                type: "POST",
                dataType: "json",
                url: "ajax.php",
                data: {content:content},
                success function (data) {
                    alert('Hello!');
                }

            });


        });

    });        
</script>

<div id="content"><?php echo $content; ?></div>

ajax.php

echo json_encode($_POST['content']); ?>

Nothing happens... WhatI really want to achieve is to get that alert box and get the return data, but I am lost since I don't get any errors or nothing.

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2条回答 默认 最新

  • dongqie7806 2012-06-11 12:21
    关注

    As @sofl said, if you change it to success:function (data) { it will work!

    Just remember that the $("a") from $("a").click(function() { called when click in a link tag like <a href"">.

    If you are using an input ou button with a class="a" you should change the code to $(".a").click(function() {

    (just add a . before a)

    PS: If you're using a link, you should set the href="" to href="#" to work.

    评论

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