doushaqing7080 2016-01-12 08:02
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从数据库中选择数据时遇到问题[重复]

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I just want to select and display data from a database. I think I am following all the tutorials etc. online but something is wrong. My code:

<?php

$user = 'root';
$pass = 'root';
$db='test';
$host ='localhost';
$name = 'ryan';


$mysqli = new mysqli($host, $user, $pass, $db);
if ($mysqli->connect_error) {
    die('Connect Error (' . $mysqli->connect_errno . ') '
            . $mysqli->connect_error);
}
    else{
        echo 'Checkpoint 1 <br>';
    }

$sql = "SELECT * FROM user WHERE name LIKE ryan";
$result = $mysqli->query($sql);
$num_results = $result->num_rows;
echo'checkpoint 2';
$row = $result->fetch_assoc();
echo'checkpoint 3';
?>

I can get to 'checkpoint 2' but for some reason the fetch_assoc() function does not do anything. I am using Netbeans, and the fetch_assoc() does not even turn green as the num_rows function does. fetch_assoc does turn green if I remove both parentheses at the end.

</div>
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  • dongpouda6700 2016-01-12 08:11
    关注

    Try this query:

    $sql = "SELECT * FROM user WHERE name LIKE 'ryan'";
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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