如何在bash shell中为php中的下一个管道生成输出？

Question

I am writing a shell to process the web log. One operation is written in php and called in the bash shell, it accept a stdin from the previous pipe and produce the output to the next pipe. I am wondering how to produce the output for the next pipe. I have already tested $stdin = fwrite(STDOUT, $data); it seems that it is not OK that way. Any solutions for me? Thank you so much!

Answer 1

I usually just use echo, or if I need a file I open "php://stdout" for writing.