dongshuang0011 2018-06-11 07:35
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在sql中使用COUNT时。 我得到错误未定义的索引

I am trying to make tables that display data on my web page but every timeI use the count function in my sql query I get the error Undefined index on line 19.

Position in/Library/WebServer/Documents/students/steve/Sites/tables.php on line 19

The php code looks like this.

<?php
include('db-connect.php');
include('top.php');

$query = 'SELECT   Nationality, COUNT(Position)
          FROM     2017_Crankworx_Results
          WHERE    Position = 1
          GROUP BY Nationality
          ORDER BY Nationality ASC';
$results = mysqli_query($link, $query) or die(mysqli_error($link));

echo '<table>';
echo '<th>Nationality</th>';
echo '<th>Position</th>';
echo '<br><br>';

while($crank = mysqli_fetch_assoc($results))
{
    echo '<tr>';
    echo '<td>'.$crank['Nationality'].'</td>';
    echo '<td>'.$crank['Position'].'</td>';
    echo '</tr>';
}

echo '</table>';

include('bottom.php');
mysqli_close($link);
?>

I you could tell me if there is something that not right with my code or if I am doing something else worng that would be great.

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3条回答 默认 最新

  • donglang1894 2018-06-11 07:40
    关注

    add " as Position" after "COUNT(Position)" in your SQL, or replace the index "Position" to "COUNT(Position)" at referencing the array

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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