du958642589 2018-03-13 13:29
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在完成函数jquery上重新加载表单

I want to pass an input value to a php session variable. With the code below, I can send the input value to the session but only appears in the alert box or if I refresh the page, which I do not want. I added the line $ ("# form1") [0] .reset (); to refresh the form and thus have the value of the session printed on the screen, but it is not working.

index.php:

<?php
    @session_start();
    error_reporting(0);
    ?>
  <!doctype html>
  <html>

  <head>
    <meta charset="utf-8">
    <title>input value to php session</title>
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
  </head>

  <body>
    <form method="post" id="form1">
      <input type="text" name="field1" id="field1" onblur="run(this)">
    </form>
    <br /><br />
    <?php echo $_SESSION['field1'];?>
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
    <script language="javascript">
      function run(sel) {
        var text = $("#field1").val();
        if (text != "") {
          $.ajax({
            type: "POST",
            url: "input.php",
            data: {
              field1: text
            }
          }); //.done(function() {alert(text)});    
        }

        if (done.(function() {
            $("#form1").reset()
          }));
      }
    </script>
  </body>

  </html>

The input.php file:

<?php
  @session_start();
  error_reporting(0);

  if (isset($_POST["field1"])){
    $_SESSION['field1'] = $_POST["field1"]; 
  }
?>
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3条回答 默认 最新

  • dpr77335 2018-03-13 13:45
    关注

    You could create a <div> around your value and change it when .done():

    To get your session value, you have to echo it and use it inside your done() callback:

    <?php
@session_start();
error_reporting(0);
?>
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>input value to php session</title>
</head>
<body>
<form method="post" id="form1">
<input type="text" name="field1" id="field1" onblur="run(this)">
</form>
<br /><br />

<!-- HERE wrap into a div with an ID -->
<div id="session-field"><?php echo $_SESSION['field1'];?></div>


<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<script language="javascript">
function run(sel) {
    var text = $("#field1").val();
    if (text != "") {
        $.ajax({
            type: "POST",
            url: "input.php",
            data: { field1: text}
        })
        // done callback using data (wha
        .done(function(data) {
            $('#session-field').html(data);
            $("#field1")[0].form.reset();
        });
    }
}
</script>
</body>
</html>

    And your input.php:

    <?php
@session_start();
error_reporting(0);

if(isset($_POST["field1"])){
   $_SESSION['field1'] = $_POST["field1"];
   echo $_SESSION['field1'] ; // echo outputs
}
?>
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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