请问我这个十进制转化二进制程序哪里有问题？

Question

#include
int main ()
{
int n,x,d,m=0;
scanf("%d",&n);
while(n--)
{
scanf("%d",&x);
if(x>0&&x<=10000)
m=0;
d=x;
do
{
m=m*10+x%2;
x=x/2;
}while(x!=0);
if(d%2!=0)
printf("%d\n",m);
if(d%2==0)
printf("%d\n",m*10);
}
return 0;
}
它编译无问题，就是运行时输入2，12等数时出现问题，5，10却没问题

Answer 1

#include <stdio.h>
#include <math.h>
int main()
{
    int n, x, d, m = 0;
    scanf_s("%d", &n);
    while (n--)
    {
        scanf_s("%d", &x);
        if (x>0 && x <= 10000)
            m = 0;
        d = x;
        for (int i = 0; x != 0; i++, x = x / 2){
            m = (x % 2) * pow((double)10, i - 1) + m;
        }

        if (d % 2 != 0)
        {
            if (d == 1)
                printf("%d\n", d);
            else
            printf("%d\n", m);
        }   
        if (d % 2 == 0)
            printf("%d\n", m * 10);
    }
    return 0;
}