根据它们的值显示7个变量

Question

I have the following variables:

$points_maxbet = 0;
$points_netbet = 0;
$points_888 = 0;
$points_sportingbet = 0;
$points_betano = 0;
$points_unibet = 0;
$points_betfair = 0;

During the execution of the script their values get incremented by different values.

Example:

if ((mysqli_real_escape_string($con, $_POST['question_01'])) == 'A')
{
    $points_maxbet += 5;
    $points_netbet += 5;
    $points_888 += 5;
    $points_sportingbet += 5;
    $points_betano += 5;
    $points_unibet += 5;
    $points_betfair += 5;
}

After they pass trough all of the increments I want to display just 3 out of those 7 variables (based on their highest values) and display some HTML for each of them.

I tried something but it would only give me the highest value variable, not the following 2 as well.

Looked for a solution on SO and Google but couldn't find any.

Let me know if I need to provide more details.

Answer 1

I would say, put them in an array at the end, sort them and pick off the top 3 elements. Sort of like the following:

<?php
    $array = array(
        'maxbet' => $points_maxbet,
        'netbet' => $points_netbet,
        'eighteighteight' => $points_eighteighteight,
        'sportingbet' => $points_sportingbet,
        'betano' => $points_betano,
        'unibet' => $points_unibet,
        'betfair' => $points_betfair);
    asort($array);
    $top3 = array_slice($array, -3);
?>

Using this in html could be as simple as something like this (code not tested yet):

<ol>
<?php foreach($top3 as $key => $value): ?>
    <li><?php echo $key; ?> - <?php echo $value; ?></li>
<?php endforeach; ?>
</ol>