在PHP中发生AJAX回发时执行jQuery代码

Question

I am trying to execute my jQuery script when the page is loaded and when partially postback has happened. However:

• function pageLoad(){}
• $(document).ready();

Don't do what I require. The code I want to be always executed is as follows:

document.getElementsByTagName("table")[0].className = "";
document.getElementsByTagName("table")[0].className = "table table-bordered";
$(".odd").addClass("success");
$(".odd").removeClass("odd");
$(".even").addClass("warning");
$(".even").removeClass("even");

Any and all help will be appreciated.

Answer 1

Okay, the answer: First, i am declaring a function on top of my page, because i want to execute it on documentload and on ajaxcallback.

Then, on the bottom of my page i set

$(document).ajaxComplete(fu);

This is what makes my function executed when te ajax callback has finished, without the need of knowing the callback's details.