如何将多个值添加到同一个数组中

Question

I want to show information on my page regarding multiple queries, each of them representing project status. To do that, i made a while loop, that adds information to an array.

The problem with that, is that i only show one of the statuses available, only the first one. Here is my code:

$exec = mysql_query($queryOntime) or trigger_error(mysql_error());
$exec1 = mysql_query($queryDelayed) or trigger_error(mysql_error());
$exec2 = mysql_query($queryPending) or trigger_error(mysql_error());        

$array_dados = array();

// All chart data
while($info = mysql_fetch_array($exec)||$info1 = mysql_fetch_array($exec1)||$info2 = mysql_fetch_array($exec2)){    
    $array_dados[] = $info; 
    $array_dados[] = $info1;
    $array_dados[] = $info2;                    
}   
return $array_dados;    

So as you can see, i have 3 queries, and i try adding all of them into an array, yet only one of the $info shows up. Why is that?

EDIT:

I removed the OR and separated my Fetch arrays, yet it still only shows the "Pending" one. Here's how it looks right now:

$exec = mysql_query($queryPending) or trigger_error(mysql_error());
$exec1 = mysql_query($queryOntime) or trigger_error(mysql_error());
$exec2 = mysql_query($queryDelayed) or trigger_error(mysql_error());    

$array_dados = array();

//All chart data
while($info = mysql_fetch_array($exec)) 
    $array_dados[] = $info; 

while($info1 = mysql_fetch_array($exec1))
    $array_dados[] = $info1;

while($info2 = mysql_fetch_array($exec2))
    $array_dados[] = $info2;

return $array_dados;

Answer 1

You could do like this also..

$exec = mysql_query($queryOntime) or trigger_error(mysql_error());
$exec1 = mysql_query($queryDelayed) or trigger_error(mysql_error());
$exec2 = mysql_query($queryPending) or trigger_error(mysql_error());        

$array_dados = array();

// All chart data
while($info = mysql_fetch_array($exec) && $info1 = mysql_fetch_array($exec1) && $info2 = mysql_fetch_array($exec2)){    
    $array_dados[] = $info; 
    $array_dados[] = $info1;
    $array_dados[] = $info2;                    
}   
return $array_dados;

Hope this would help.