dongpo1599 2016-01-06 17:22
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如何使用PHP将数据放到jquery并放入php? [关闭]

I have this code but I dont know how to fix this...

When I run this in my site and click this link

<a href="#add"> <img src="image/addtocart.png" width="50%" style="margin-left: 170px;"></a>

the data from $row[product_name]

will be not store in this class

<!----    POPUP #CHOOSE SIZE    ----->  

    <a href="#x" class="overlay" id="add"></a>

    <div class="box">
        <h2><span style="color:blue;font-weight:bold">Choose Size</span></h2>

        <?php echo "<h5>$row[product_name]</h5></br>"; ?>

    <?php
         $sql1="SELECT product_size, product_price FROM products where product_name='$row[product_name]'";

    foreach ($conn->query($sql1) as $row1){
    echo " $row1[product_price]";
    echo "<p><button name='submit' type='submit' class='a_demo_five' value='$row1[product_size]'>$row1[product_size] P$row1[product_price].00</button></p>"; 

    }
    ?>

This is my original code:

<?php
         include 'core/admin/admin_db.php';

         $sql="SELECT DISTINCT product_name, product_description, product_image FROM products WHERE product_category = 'Chicken' GROUP BY product_name";
         echo"<div class='scroll2'>";
         foreach($conn->query($sql) as $row){
         echo "<li>";
         echo "<div class='grow2 pic'><img src='$row[product_image]'></div>";
     echo "<h5>$row[product_name]</h5></br>";



  ?>


<a href="#add"> <img src="image/addtocart.png" width="50%" style="margin-left: 170px;"></a>




<!----    POPUP #CHOOSE SIZE    ----->  

<a href="#x" class="overlay" id="add"></a>

<div class="box">
    <h2><span style="color:blue;font-weight:bold">Choose Size</span></h2>

    <?php echo "<h5>$row[product_name]</h5></br>"; ?>

<?php
     $sql1="SELECT product_size, product_price FROM products where product_name='$row[product_name]'";

foreach ($conn->query($sql1) as $row1){
echo " $row1[product_price]";
echo "<p><button name='submit' type='submit' class='a_demo_five' value='$row1[product_size]'>$row1[product_size] P$row1[product_price].00</button></p>"; 

}
?>

Thanks In Advance!

  • 写回答

1条回答 默认 最新

  • douzhi6365 2016-01-06 17:49
    关注

    You should not enclose variable in double quote as they are meant for string. You are also missing out some closing bracket which make the whole code not functioning.

    Note that you must use different id for different item, or else page will only load the first class when you click add.

    <?php
    include 'core/admin/admin_db.php';
    $sql = "SELECT DISTINCT product_name, product_description, product_image FROM products WHERE product_category = 'Chicken' GROUP BY product_name";
    echo "<div class='scroll2'>";
    foreach($conn->query($sql) as $row){
        $product_name = $row['product_name'];
        echo "<li>";
        echo "<div class='grow2 pic'><img src='".$row['product_image']."'></div>";
        echo "<h5>".$product_name."</h5>";
        echo "<a href='#add_".$row['product_id']."'><img src='image/addtocart.png' style='width:50%;margin-left:170px;'></a>";
        // POPUP #CHOOSE SIZE
        echo "<a href='#x' class='overlay' id='add_".$row["product_id"]."'></a>";
        echo "<div class='box'>";
        echo "<h2><span style='color:blue;font-weight:bold'>Choose Size</span></h2>";
        echo "<h5>".$product_name."</h5>"; 
        $sql1="SELECT product_size, product_price FROM products WHERE product_name='$product_name'";
        foreach ($conn->query($sql1) as $row1){
            echo $row1['product_price'];
            echo "<p><button name='submit' type='submit' class='a_demo_five' value='".$row1['product_size']."'>".$row1['product_size']." P".$row1['product_price'].".00</button></p>"; 
        }
        echo "</div>";
        echo "</li>";
    }
    echo "</div>";
    ?>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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