dongruyan4948 2012-04-14 21:45
浏览 57

使用jQuery ajax json,php将项目填充到Select中

simple code to populate items into a Select using jQuery ajax json, php on first menu change it must make ajax call to fruit-varities.php to get a json array and create the second menu main page

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
    <html>
    <head>
    <title>Load JSON data with jQuery, PHP and MySQL</title>
    <link rel="stylesheet" type="text/css" href="/css/main.min.css?1319445416"  />
    <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js" type="text/javascript"></script>
    <script type="text/javascript">
    $(document).ready(function() {
         $('#mark').change(function() {
             $.get("fruit-varities.php",
                {'idcategory' : idc },
                function(data){
                    var select = $('#series').empty();
                    $.each(data.values, function(i,item) {
                        select.append( '<option value="'
                                             + item.fruit_id
                                             + '">'
                                             + item.name
                                             + '</option>' ); 
                    });
                }, "json");
    });
    });
</script>
    </head>
    <body>
    <form>
    <select id="mark">
      <option value="">--</option>
      <option value="bmw">BMW</option>
      <option value="audi">Audi</option>
    </select>
    <select id="series">
    </select>
    <div id="view">
    </div>
    </form>
    </body></html>

and here is fruit-varities.php

<?php
if(isset($_GET['idcategory'])){
$item = Array(
    Array
        (
            "fruit_id" => "1",
            "name" => "Apple",
            "variety" => "Red Delicious"
        )

);
}
echo json_encode(item);
?>

this is doesn't work at it all don't know why ? everything seems to be fine for me but i don't know what is the problem

  • 写回答

1条回答 默认 最新

  • dpfln86244 2012-04-14 22:06
    关注

    You don't have "idc" variable in your page, but you are using it as an Ajax request parameter's value. It does not metter, what value 'idcategory' parameter should have (by analyzing your php script), so you could replace {'idcategory' : idc } with {'idcategory' : ''}.

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