如何在php中使用in_array并将数组作为needle，但在至少有一个值匹配时返回true

Question

Here is my in_array code

$array = array('a', 'b', 'c');

if(in_array(array('p', 'c'), $array)){
    echo "found";
}else{
    echo "not found";
}

it returns not found, but actually I want it to return found, because there is one value match c .

Answer 1

Your idea can be realized by using array_intersect and count functions.
If there's at least one matched item between two arrays - count will return the number of matched items (1 or more):

$needle = array('p', 'c');
$haystack = array('a', 'b', 'c');

echo (count(array_intersect($needle, $haystack))) ? "found" : "not found";
// will output: "found"

http://php.net/manual/en/function.array-intersect.php