如何回显包含文件的文件名[根据文件运行更改页面标题]

Question

I tried using php predefined variables but no function seems to work for me.

index.php, page2.php, page3.php contains:

include 'header.php';

now, i want my header.php to echo different title tags depending which file called it.

I tried running echo FILE but echo header.php, rather than index.php or page2.php,.. etc.

is there a way to handle this?

Answer 1

What you could do is set a variable like $title on every of your pages (i.e. index.php, page2.php and page3.php) with your desired title and then echo this variable in the header.php like this (example for index.php):

$title = "Welcome Page";
include("header.php");

And in header.php:

echo $title;

To my knowledge there is no way in determining which file A included an other file B from within file B. For the opposite, determining all included files there however exists the function get_included_files().