douxia2053 2016-08-04 12:39
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SQL OFFSET语法错误

I'm trying to increase the offset every time by 3, so I used a variable that is increased by 3 every time a button is clicked (using ajax).

However, I keep getting a syntax error when using OFFSET.

Is this the correct way to do it?

$web = "SELECT * FROM `db` WHERE catid = 9 AND state = 1 ORDER BY ordering LIMIT 0,".$_POST['limit']." OFFSET ".$_POST['limit']."";

limit is increased by 3 every button click, if I leave out OFFSET, it works, but it keeps loading all items again, instead of just 3 new items.

My error:

There was an error running the query [You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'OFFSET 3' at line 1]

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  • douqi2804 2016-08-04 12:41
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    The syntax should be:

     LIMIT ".$_POST['limit']." OFFSET ".$_POST['limit']."";
    

    The 0 conflicts with OFFSET.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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