如何在一个表中统一3个文件？

Question

I have a test script, that generate txt file with answers. And have 2 txt files with the correct answers. I want: 1) Unite all files in one table, like:

<table>
<tr>
<td>№ of question</td>
<td>data from file 1</td>
<td>data from file 2</td>
<td>data from file 3</td>
</tr>
...
</table>

2) I want to replace id in this files on text from DB (MySQL). I have table with question and answers with similar id (like in txt files).

All files have structure like:

1|3
2|4
3|1

where first number - is id of a question, and second is a variant of answer.

I start coding, but don't know how to include data from files:

// Slect from DB
$qsel=mysql_query("SELECT `qid`, `qtext` from `questions` ORDER BY `qid`");

// Open file 1 
$key1=fopen("data/test_1_key1.txt", "r");
$k1=explode("/r/n", $key1);

// Open file 2 
$key2=fopen("data/test_1_key2.txt", "r");
$k2=explode("/r/n", $key2);

$rtable='<table border="1" cellspacing="0" cellpadding="3">
    <tr>
      <th width="40%">Q</th>
      <th width="20%">A 1</th>
      <th width="20%">A 2</th>
      <th width="20%">NAME</th>
    </tr>';
  while($q=mysql_fetch_row($qsel))
  {

    $rtable.='<tr><td><b>'.$q['1'].'</b></td>'; 
    $rtable.='<td>data from file 1</td>'; 
    $rtable.='<td>data from file 2</td>'; 
    $rtable.='<td></td>'; 
  }
  echo '</table>'.$rtable;

Answer 1

I would first fetch the textfiles and convert it into indexed array:

$tmp1 = file('text1.txt');
$data1 = array();
foeach($tmp1 as $line)
{
    list($key1, $val1) = explode("|", $line);
    $data1[$key1] = $val1;
}

and then, on mysql fetch loop, just use the indexed array:

while($q=mysql_fetch_row($qsel))
{

    $rtable.='<tr><td><b>'.$q['1'].'</b></td>'; 
    $rtable.='<td>' . ( isset( $data1[ $q['0'] ] ) ? $data1[ $q['0'] ] : '' ) . '</td>'; 
    $rtable.='<td>data from file 2</td>'; 
    $rtable.='<td></td>'; 
}