获取url参数：如果在输入字段的name属性中使用了第三个括号，则JavaScript无效

Question

I have used the below JavaScript code to get the parameter from the URL and checked the input field. It is working fine if I don't use name="community[]" third bracket in my input field. If I used third bracket in JavaScript code then it is not working.

html

<input type="checkbox" id="type" name="community[]" value="<?php echo $comvalue;?>">

JavaScript

var i = document.location.href.lastIndexOf('?');
document.location.href.substr(i+1).replace(/community=/g,'').split('&');
$('input[name="community"]').prop('checked',function(){
     return $.inArray(this.value,types) !== -1;
});

Answer 1

The issue is because you're missing the [] from the name attribute in your selector:

var types = ['A', 'C'];

$('input[name="community[]"]').prop('checked', function() {
  return $.inArray(this.value, types) !== -1;
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="checkbox" id="type" name="community[]" value="A">
<input type="checkbox" id="type" name="community[]" value="B">
<input type="checkbox" id="type" name="community[]" value="C">

</div>