dtcpvz8162 2010-07-09 00:33
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在PHP的curl中指定multipart / form-data的每个部分的Content-Type

How do I specify the content type of a specific part of a multipart/form-data request? The content type for the image is being sent as application/octet-stream, however the server is expecting it to be image/jpeg. This causes the server to deny my request.

$data["file"] = "@/image.jpg";
$data["title"] = "The title";
$data["description"] = "The description";

//make the POST request
$curl = curl_init();
curl_setopt($curl, CURLOPT_URL,$url);
curl_setopt($curl, CURLOPT_VERBOSE, 1);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_HTTPHEADER, $header);
curl_setopt($curl, CURLOPT_POSTFIELDS, $data);
$result = curl_exec($curl);

This is the relevant parts of the request:

Content-Type: multipart/form-data; boundary=----------------------------fc57f743c490

------------------------------fc57f743c490
Content-Disposition: form-data; name="file"; filename="NASA-23.jpg"
Content-Type: application/octet-stream

I want it to be:

Content-Type: multipart/form-data; boundary=----------------------------fc57f743c490

------------------------------fc57f743c490
Content-Disposition: form-data; name="file"; filename="NASA-23.jpg"
Content-Type: image/jpeg
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1条回答 默认 最新

  • dpowt82802 2010-07-09 01:58
    关注

    You would do something like this,

    $data["file"] = "@/image.jpg;type=image/jpeg";
    
    //make the POST request
    $curl = curl_init();
    curl_setopt($curl, CURLOPT_URL,$url);
    curl_setopt($curl, CURLOPT_VERBOSE, 1);
    curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($curl, CURLOPT_HTTPHEADER, $header);
    curl_setopt($curl, CURLOPT_POSTFIELDS, $data);
    $result = curl_exec($curl);
    
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