dsh1956 2014-03-19 22:47
浏览 21
已采纳

使用PHP解决最忙碌的一天

I have a table with a timestamp in unixtimestamp for everytime someone logs into the system. I would like to work out the busiest day.

Im a little lost as to where to start, i believe its that you need to work out a count for each day stored into the database (or some kind of string between start and end of the logs?)

Database Structure for logs

Example :

user  | action         | timestamp
admin | User Logged In | 1395257767

User being "Username"

Action being "User Logged In"

Timestamp being Unixtimestamp given at the time they login to the system.

Any help would be a great start

SQLFiddle - http://sqlfiddle.com/#!2/66d4293

  • 写回答

3条回答 默认 最新

  • dongzhou5344 2014-03-19 22:54
    关注

    Try something like thi.

    SELECT COUNT(*) c, DATE(FROM_UNIXTIME( timestamp) ) day FROM log 
    GROUP BY  day ORDER BY c DESC LIMIT 1;
    

    DATE(FROM_UNIXTIME( timestamp )) converts to a datetime and then a date.

    By the way, you might consider storing your dates as datetime or timestamp structures. Storing as unix timestamps and then having to convert to useable dates is less than ideal.

    http://sqlfiddle.com/#!2/a53d1/2

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(2条)

报告相同问题?

悬赏问题

  • ¥50 汇编语言除法溢出问题
  • ¥50 C++实现删除N个数据列表共有的元素
  • ¥15 Visual Studio问题
  • ¥15 state显示变量是字符串形式,但是仍然红色,无法引用,并显示类型不匹配
  • ¥20 求一个html代码,有偿
  • ¥100 关于使用MATLAB中copularnd函数的问题
  • ¥20 在虚拟机的pycharm上
  • ¥15 jupyterthemes 设置完毕后没有效果
  • ¥15 matlab图像高斯低通滤波
  • ¥15 针对曲面部件的制孔路径规划,大家有什么思路吗