dongmo2324 2013-06-23 21:22
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如何读取目录和过滤文件,然后回显它们?

Hello everyone im trying to read a directory called people which is filled with php,html,png,jpeg and other formats. I am trying to filter the files i want the php and html files and then echo them out.

Here is my attempt which didn't work since it didn't echo any files:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Khviii ICT</title>
</head>

<body>
<div align="center" ><h1>Welcome to KHVIII ICT</h1></div>
<?php
$dir="/people";
$allowed_view= array("php","html");
$files=scandir($dir);
foreach ($files as $file)
{
        $filexplosion=strtolower(end(explode('.',$file)));
    if (in_array($allowed_view,$filexplosion)) 
        {
    echo $file;
    } 
}
?>
</body>
</html>
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3条回答 默认 最新

  • douban2014 2013-06-24 17:59
    关注

    After a few goes i have worked it out i am using gelb(). Here is the code:

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
    <html xmlns="http://www.w3.org/1999/xhtml">
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
    <title>khvii index</title>
    </head>
    
    <body>
    <?php
    foreach (glob("people/"."*.php",GLOB_BRACE) as $filename) {
        $phpexplode = end(explode("/",$filename));
        echo'<a href="'.$filename.'"><input type="button" value="'.$phpexplode.'"></a><br />';
    }
    foreach (glob("people/"."*.html",GLOB_BRACE) as $filename) {
        $htmlexplode = end(explode("/",$filename));
        echo'<a href="'.$filename.'"><input type="button" value="'.$htmlexplode.'"></a><br />';
    }
    ?>
    </body>
    </html>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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