dqjl0906 2014-12-27 23:43
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替换[url = URL]正则表达式

looking for a way to remove any text that is

[url=]

That would be easy, but the url itself is a URL I dont have control of.

e.g or urls:

[url=wqffqwfq] [url=qwfwqfqf]

etc.

Looking for a preg replace, currently have this:

$post_text = preg_replace('%\[URL[^\]]*\][^\[\]]*|\[/URL[^\]]*\]%i', '', $post_text);

But that removes the image that comes after the url.

Thanks.

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  • duanpanhuo0618 2014-12-27 23:53
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    I think you use too much escape characters. You can however use lazy capture groups:

    $string = '[foo] buz [url=wqffqwfq] qux [bar] foobar [url=qwfwqfqf] faq';
    $pattern = '/\[url=(.*?)\]/i';
    $replace = '';
    $string = preg_replace($pattern,$replace,$string);
    //$string = '[foo] buz  qux [bar] foobar  faq';
    

    If the assignment (=) character is optional, you can use the /\[url(.*?)\]/i pattern.

    Information: .*? means a non-greedy capture: this means that . is captures, as long as there is no way to escape the group. From the moment it is possible, the regex mechanism escapes the group.

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