如何使用Javascript提交POST变量？

Question

So I am trying to submit a variable and the name of the variable via a form. I switched a button from submit to button because I need additional validation.

Anyway, here's the button now:

<button type="button" onclick="subForm()" name="del" id="deletebutton" value="'.$org.'">Delete</button>

Here's my current validation:

<script type="text/javascript">
function subForm() 
{
    if(confirm("Are you sure you want to delete this?"))
        document.forms["addorg"].submit();
   else
       return false;

}
</script>

And here's my script on the other side:

if (isset($_POST["del"])  && ($_POST['del'] !== '')) {
    $del = mysql_real_escape_string(html2txt($_POST['del']));
    $resfile = mysql_query('SELECT file_loc from organization WHERE org_id = '.$del);
    $org_name = mysql_real_escape_string(html2txt($_POST['orgname']));

    if (!$resfile) 
        header('Location: '.$admin.'?error=query');

    while ($filerow = mysql_fetch_array($resfile)) {
        $fileplace = $filerow['file_loc'];
        unlink(".".$fileplace);
        rmdir($org_name);
    }

    mysql_query("DELETE from organization where org_id='".$del."'");
    header('Location: '.$admin);
}

It is not currently deleting the records that I want. How do I pass along the "del" name to the other page?

Answer 1

You can use <input type="hidden">:

echo '<input type="hidden" name="org_id" value="'.$org_id.'" />'

This should render something like:

<input type="hidden" name="org_id" value="1" />

Using this code you can access the hidden field data using:

$org_id = $_POST['org_id'];