将返回的字符串传递给另一个字符串并在if语句中使用它[关闭]

Question

I have this piece of code:

<?php
            require_once 'Membership.php';
    $membership = New Membership();
    $AccountType = $membership->is_Account($currUser);
    if ($AccountType == 'S') {
        echo '<li>';
        echo $AccountType;
        echo '</li>';
    }
   ?>

Which calls upon a different document membership.php with a function that does this:

function is_Account($currUser){
    //Find out if user is a buyer or a seller
    $mysql = New Mysql();
    $mysql->get_Account($currUser); 
}

Which for organisational reasons - goes to a document (this bit works, as other functions work successfully) that does this:

function get_Account($currUser) {
    $mysqli = new mysqli(DB_SERVER, DB_USER, DB_PASSWORD, DB_NAME);
    if (!$mysqli) {
        die('There was a problem connecting to the database.');
    }       
    $queryAcct = "SELECT Id
            FROM Users
            WHERE Username = '$currUser'
            LIMIT 1";
    if ($Result = $mysqli->query($queryAcct)){
        if (!$Result) {
            echo 'Could not run query: ' . mysql_error();
            exit;
        }
        else {
            $row = $Result->fetch_assoc();
            return $row["Id"];
        }
    }
    $mysqli->close();
}

So - that last function has an issue. I want to use the Id returned so that for example if it is 1, I display that content pertaining to Id 1 (multiple people will have that Id number as it is a tier system).

Basically - I have no idea why it isnt returning the Id to the original bit of code. I assume i've done something wrong. I just don't know how to fix it.

Echoing $row["Id"] will work so I know that bit is fine and its not an sql issue. But that isnt what I want to do.

Answer 1

You need to return the value from get_Account() in your is_Account() function:

return $mysql->get_Account($currUser);