使用mysqli从数据库中获取所有结果

Question

please check out my code below. With that class I am able to display results like so:

$connectTest    = new testResults();
$test       = $connectTest->grabResults(test, id, id);

echo $test['id'];
echo $test['name'];
echo $test['address'];

In my database I have several fields in the "test" table. I go to my page using index.php?id=1. With this I am displaying just the results from one row because it grabs all results WHERE id = 1.

What I need is the class below to display multiple results. It just displays one row. But if I have multiple rows with id = 1 I would like to display these results, but I cannot get it to work. I have tried a lot of things but I always end up with just one result.

class:

class testResults
{

    public function grabResults($table, $field, $id)
    {
        $result = $this->db->mysqli->query("SELECT * FROM $table WHERE $field = $id");

        $resultData[] = array();

        if(!$result)
        {
            return false;
        }

        while($row = $result->fetch_assoc())
        {
            $rows[] = $row;
        }

            foreach ($rows as $resultData)
            {
                return $resultData;
            }
    }
}

Edit:

Array ( [id] => 25 [name] => test [status] => 1 )
Array ( [id] => 25 [name] => test [status] => 3 )
Array ( [id] => 25 [name] => test [status] => 5 )
Array ( [id] => 25 [name] => test [status] => 4 )

Array ( [id] => 26 [name] => test [status] => 1 )
Array ( [id] => 26 [name] => test [status] => 3 )

Array ( [id] => 27 [name] => test [status] => 1 )
Array ( [id] => 27 [name] => test [status] => 3 )
Array ( [id] => 27 [name] => test [status] => 5 )
Array ( [id] => 27 [name] => test [status] => 4 )
Array ( [id] => 27 [name] => test [status] => 2 )
Array ( [id] => 27 [name] => test [status] => 4 )
Array ( [id] => 27 [name] => test [status] => 1 )

I am getting results as above, any way to easily display these results in an echo? For each id there are different results, so results will vary with each query. So I would like to display results in a table for example like so:

echo '<table>
<tr>
<td>$id</td>
<td>$name</td>
<td>$status</td>
</tr>
</table>';

So all results will be displayed like in a while loop.

Answer 1

You can just return the array from function and then loop in your script

while($row = $result->fetch_assoc())
{
    $rows[] = $row;
}
return $rows;

The you can loop in your script

$test = $connectTest->grabResults(test, id, id);
foreach($test as $value)
{
     print_r($value);
}

Upon OP edit

If you need to print them separate you can access all elements with variable name and scopes with keys as follow

$test = $connectTest->grabResults(test, id, id);
echo '<table>';
foreach($test as $value)
{
     echo '<tr>
             <td>'.$value['id'].'</td>
             <td>'.$value['name'].'</td>
             <td>'.$value['status'].'</td>
           </tr>';
}           
echo '</table>';