dreamy1992 2013-11-21 15:23
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如何识别这些媒体链接以设置适当的播放器?

I've real complex idea, Okay anyway let say we have the following links

    www.some_site.com/test.wmv                   // media player
    www.some_site.com/test.mp4                  // jwplayer
    www.some_site.com/test.flv                 // jwplayer
    www.some_site.com/test.rmvb               // real player
    www.some_site.com/test.mov               // quick time
    www.youtube.com/watch?v=cyvX3_3nqfc     // jwplayer

Looks like media links so as far as I know there is no player that support all extensions hence I'm going to use for each of those links its player based on its extension.

Example 1 (for wmv will embedded Windows media player code)

  <object type="video/x-ms-wmv"
  data="test.wmv"
  width="400" height="350">
  <param name="src" value="test.wmv" />
  <param name="autostart" value="true" />
  <param name="controller" value="true" />
  </object>

Example 2 (for mov will embedded quick time code)

    <object classid="clsid:02BF25D5-8C17-4B23-BC80-D3488ABDDC6B"
    codebase="http://www.apple.com/qtactivex/qtplugin.cab"
    width="400" height="350">
    <param name="src" value="test.mov" />
    <param name="controller" value="true" />
    <param name="autoplay" value="true" />
    <!--[if !IE]>-->
    <object type="video/quicktime"
      data="test.mov"
      width="400" height="350">
    <param name="autoplay" value="true" />
    <param name="controller" value="true" />

Okay you must have got my point so the question is how using PHP can get the extension of each file of the link in order call its proper player

if ($ext === 'wmv' || $ext === 'asf') {

echo "media player";

} else if($ext === 'mov') {

echo "qick time";


} else if($ext === 'rmvb') {

echo "real player";

} else if($ext === 'youtube' || $ext === 'flv' || $ext === 'mp4') {

echo "jwplayer is good";

} else {

echo "die well";

}

What For

In fact I'm trying write class that can identify the link then call its proper player embedded code to my webpage and will to support as many as I can of different media extensions so this is basic example that would really helps me a lot.

  • 写回答

1条回答 默认 最新

  • douyongwan5946 2013-11-21 15:44
    关注

    Here's one approach, it should be flexible enough.

    <?php
    class VideoRenderer {
        protected
            $engines = array();
    
        public function register(VideoRendererEngine $engine) {
            array_push($this->engines, $engine);
            return $this;
        }
    
        public function render($video) {
            foreach ($this->engines as $engine) {
                if ($engine->accepts($video)) {
                    return $engine->render($video);
                }
            }
            return false;
        }
    }
    
    interface VideoRendererEngine {
        /**
         * @return bool Whether this Engine can render the video supplied
         */
        public function accepts($video);
        /**
         * @return string Rendered HTML
         */
        public function render($video);
    }
    
    class WmvVideoEngine implements VideoRendererEngine {
        public function accepts($video) {
            return 'wmv' === substr($video, -3, 3);
        }
    
        public function render($video) {
            return '<object type="video/x-ms-wmv"
                data="' . $video . '"
                width="400" height="350">
                <param name="src" value="test.wmv" />
                <param name="autostart" value="true" />
                <param name="controller" value="true" />
            </object>';
        }
    }
    
    class AsfVideoEngine implements VideoRendererEngine {
        public function accepts($video) {
            return 'wmv' === substr($video, -3, 3);
        }
    
        public function render($video) {
            return '<object type="video/x-ms-wmv"
                data="' . $video . '"
                width="400" height="350">
                <param name="src" value="test.wmv" />
                <param name="autostart" value="true" />
                <param name="controller" value="true" />
            </object>';
        }
    }
    
    $renderer = new VideoRenderer;
    $renderer->register(new WmvVideoEngine);
    $renderer->register(new AsfVideoEngine);
    echo $renderer->render('http://www.example.com/test.wmv');
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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