PHP - 使用foreach和数组

Question

I'm struggling to get the correct syntax to to parse out the values from an array to use with the foreach loop. I have an array:

$contacts_array

which contains one or more names which I need to search on. The array looks like this:

Array
(
    [0] => PR1010

    [1] => PR1086
)   

If I was to manually generate the required PHP code with a known number of names it would look like this where there are 2 names to search on:

// Create first find request
$findreq1 =$fm->newFindRequest('Contacts');

// Create second find request
$findreq2 =$fm->newFindRequest('Contacts');


// Specify search criterion for first find request 
$findreq1->addFindCriterion('Name', $searchTerm);

// Specify search criterion for second find request 
$findreq2->addFindCriterion('Suburb', $searchTerm);;

// Add find requests to compound find command 
$request->add(1,$findreq1); 
$request->add(2,$findreq2); 

I need to generate the equivalent code for every name in the array. I know I need to use something like:

foreach($contacts_array as $contact_array => $value) 
{
} 

as well as:

$num = 1
$num++; } /* foreach record */

I'm just not sure how to bring this all together so that it increments the $findreq1 variables as I go. All my attempts so far generate errors. If anyone can show me how to combine this together that would be greatly appreciated as I'm learning PHP as I go.

Thanks

Answer 1

<?php 
    for($i = 0; $i < count($contacts_array); $i++) { 
        ${'findreq' . ($i+1)} = $fm->newFindRequest('Contacts');
        ${'findreq' . ($i+1)}->addFindCriterion('Name', $contacts_array[$i]);
        $request->add($i+1, ${'findreq' . ($i+1)});
    }
?> 

Read more about Dynamic variable names in PHP