抓取后重复数据库中的重复数据[重复]

Question

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• Reference - What does this error mean in PHP? 34 answers

I am using simple html dom to crawl data from a site into my database and display on my web page. But every time i run the file, duplicate data is also inserted into database.How can i keep check on whether data is already present in database or not? Here is my file for crawling:

 <?php

 $con=mysqli_connect("localhost","root","","crawling");\

 mysql_connect("localhost", "root", "")or die("cannot connect"); 
 mysql_select_db("crawling")or die("cannot select DB");


 include "domcrawl.php";
 $url="http://www.bgr.in/category/reviews/";
 $html=file_get_html($url);
 //$arr=$html->find('table[class=findList] tbody tr td[class=result_text]');
 $m=$html->find('img');

 $b=$html->find('a');

 $c=$html->find('p');  

 $imghead = $b[21]->innertext;

 $img = $m[3];

 $imgtext = $c[0];


 $sql = sprintf("INSERT INTO image1
 ( head, image, text, name)
 VALUES
 ( '%s', '%s', '%s', '%s')",

 mysql_real_escape_string($imghead),
 mysql_real_escape_string($img),
 mysql_real_escape_string($imgtext),
mysql_real_escape_string("gm")
);
 mysql_query($sql);





 $sql = "SELECT head FROM image1 WHERE name='gm'";
 $sql1 = "SELECT image FROM image1 WHERE name='gm'";
 $sql2 = "SELECT text FROM image1 WHERE name='gm'";
 $result = mysql_query("$sql");
 $result1 = mysql_query("$sql1");
 $result2 = mysql_query("$sql2");

  $head_get= mysql_result($result, 0);
 $img_get= mysql_result($result1, 0);
 $text_get= mysql_result($result2, 0);
 echo "<br><br>";

 echo $head_get;
 echo "<br><br>";
 echo $img_get;
 echo $text_get;


  ?>

</div>

Answer 1

Assuming 'date' => $node->getElementsByTagName('pubDate')->item(0)->nodeValue is line 11, there seems to be no element with tag pubDate, which is why $node->getElementsByTagName('pubDate')->item(0) returns either null or false.