dongtao5055 2017-01-05 17:02
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存储随机值，$ _SESSION和$ _POST问题

I'm making something similar a captha, the not working part is the IF, under if(isset($_POST['submit'])), that always returns false. I think. Tried a lot ways with no luck... Anyway, I have followed this solution https://stackoverflow.com/a/21504949/4167976 without success.

Here is my test php and html:

<?php
session_start();
$char = "abcdefghijklmnopqrstuvwxyz1234567890";
$code = $char[rand(0,35)].$char[rand(0,35)].$char[rand(0,35)].$char[rand(0,35)].$char[rand(0,35)].$char[rand(0,35)];
$_SESSION["testcode"] = $code;
echo $_SESSION["testcode"]."<br>"; // echo here only for testing

if(isset($_POST['submit'])) {
    $code1 = mb_substr($_POST['fullcode'], 0, 5);
    $code2 = mb_substr($_POST['fullcode'], -6);

    if ($code2 == $_SESSION["testcode"])
        {echo "The code is correct!";}
    else
        {echo "Wrong code!";}

    // unset($_SESSION['testcode']); // ???
}

?>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>

<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
<input type="text" name="fullcode">
<input type="Submit" name="submit" value="Submit!">
</form>

</body>
</html>

Please, tell me what and where I'm wrong... Thanks! :)

EDIT:

<?php
session_start();

if (!isset($_SESSION["testcode"])) {
    $char = "abcdefghijklmnopqrstuvwxyz1234567890";
    $code = $char[rand(0,35)].$char[rand(0,35)].$char[rand(0,35)].$char[rand(0,35)].$char[rand(0,35)].$char[rand(0,35)];
    $_SESSION["testcode"] = $code;
}

if(isset($_POST['submit'])) {
    $code1 = mb_substr($_POST['fullcode'], 0, 5);
    $code2 = mb_substr($_POST['fullcode'], -6);

    if ($code2 === $_SESSION["testcode"])
        {echo "The code is correct!<br>";}
    else
        {echo "Wrong code!<br>";}

    unset($_SESSION['testcode']);
    $char = "abcdefghijklmnopqrstuvwxyz1234567890";
    $code = $char[rand(0,35)].$char[rand(0,35)].$char[rand(0,35)].$char[rand(0,35)].$char[rand(0,35)].$char[rand(0,35)];
    $_SESSION["testcode"] = $code;
}
?>

Finally, get a new code IF the condition is false!

  • 写回答

1条回答 默认 最新

  • dsvjw20866 2017-01-05 17:18
    关注
    <?php
session_start();

// first request.
// if not set session 'testcode' and set it, else do nothing.
// prevent session be covered.
if (!isset($_SESSION["testcode"])) {
    reFreshCode();
}

if(isset($_POST['submit'])) {
    $code1 = mb_substr($_POST['fullcode'], 0, 5);
    $code2 = mb_substr($_POST['fullcode'], -6);
    if ($code2 == $_SESSION["testcode"])
        echo "The code is correct!";
    else {
        // get a new code IF the condition is false!
        echo "Wrong code!";
        echo “new code：”.reFreshCode();
    }
}

function reFreshCode() {
    $char = "abcdefghijklmnopqrstuvwxyz1234567890";
    $code = $char[rand(0,35)].$char[rand(0,35)].$char[rand(0,35)].$char[rand(0,35)].$char[rand(0,35)].$char[rand(0,35)];
    return $_SESSION["testcode"] = $code;
}
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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