使用Javascript或PHP创建XML文件

Question

I have a XML file as follows:

<bracelets>
     <photo filename="b1.jpg" thumbnail="a1.jpg" description="aa" />
     <photo filename="b2.jpg" thumbnail="a2.jpg" description="aa" />
     <photo filename="b3.jpg" thumbnail="a3.jpg" description="aa" />
     <photo filename="b4.jpg" thumbnail="a4.jpg" description="aa" />
</bracelets>

I want to fetch all image names into a .php page.

I am using this now.

$bracelets = simplexml_load_file($bracelets_xml);
        x = xmlDoc.getElementsByTagName('photo')[0].attributes;
        for (i = 0; i < x.length; i++) {
            document.write(x[i].childNodes[0].nodeValue);
        }​

But currently I am only able to fetch one image.

How can I fetch all images instead?

Answer 1

If PHP is an option, have you looked at SimpleXML yet?

In your case:

    $bracelets_xml = <<<XML
    <bracelets>
            <photo filename="b1.jpg" thumbnail="a1.jpg" description="aa" />
            <photo filename="b2.jpg" thumbnail="a2.jpg" description="aa" />
            <photo filename="b3.jpg" thumbnail="a3.jpg" description="aa" />
            <photo filename="b4.jpg" thumbnail="a4.jpg" description="aa" />
    </bracelets>
XML;

$bracelets = new SimpleXMLElement($bracelets_xml);

foreach($bracelets -> photo as $photo) {
    $counter++;
    echo "Photo " . $counter . ":
";
    echo "Filename : " . $photo['filename'] . "
";
    echo "Thumbnail : " . $photo['thumbnail']. "
";
    echo "Description : " . $photo['description']. "
";
}

Obviously the output above isn't what you want, but you could output it however you want depending on the context.