dqnhfbc3738 2011-05-13 20:02
浏览 35
已采纳

查询:根据日期计算平均住宿价格

periods

Hello all,

I need to create a query for house search, that would match in database user entered data: date when they want to move in and leave, number of people they have in group and price per night.

Lets say user searched for house:

dates: from 2011-01-15 to 2011-03-01 (see on picture period A1C1), for 3 people, and he is willing to spend from $90 to $125 dollars per night.

This is my manual calculations for this search:

  • dates available in database
  • total number of dates user wants to stay is: 44 days
  • price for the first period 2011-01-15 to 2011-01-25 is 10 days * $100 = $1000
  • price for the second period 2011-01-25 to 2011-02-14 is 20 days * $120 = $2400
  • price for the third period 2011-02-14 to 2011-03-01 is 14 days * $140 = $1960
  • total average price per night = 1000 + 2400 + 1960 / 44 = $121.8
  • price and number of people matches user input, so we display this house

If you merge dates and calculate average price per night for the given period, search script should match array of data provided above.

My question is this: How my query should look like to calculate quickly if user data matches records in database.

I was thinking about using SQL DATEDIFF function and then multiply by price ... etc but it looks to me pretty complex.

I will appreciate any advice.

Thank you

UPDATE

Here is my database schema:

Table "apt_search_periods" which stores all merged dates (continuous dates from availability table)

+-----------+------------+------------+-----------+--------------+--------+
| period_id | start_date | end_date   | rental_id | nb_of_people | merged |
+-----------+------------+------------+-----------+--------------+--------+
|        21 | 2011-03-31 | 2012-03-31 |       548 |            4 | y      |
+-----------+------------+------------+-----------+--------------+--------+

Table "apt_search_periods_avail" linking merged dates with availability table

+----+-----------+-----------------+
| id | period_id | availability_id |
+----+-----------+-----------------+
| 21 |        21 |           20953 |
| 22 |        21 |           20952 |
| 23 |        21 |            4033 |
+----+-----------+-----------------+

Table "availability" with expanded dates and prices

+-------+-----------+------------+------------+--------------+--------------+
| id    | rental_id | start_date | end_date   | nb_of_people | rent_per_day |
+-------+-----------+------------+------------+--------------+--------------+
| 20952 |       548 | 2011-03-31 | 2011-07-01 |            4 |          575 |
|  4033 |       548 | 2011-07-01 | 2011-09-01 |            4 |          680 |
| 20953 |       548 | 2011-09-01 | 2012-03-31 |            4 |          575 |
+-------+-----------+------------+------------+--------------+--------------+
  • 写回答

1条回答 默认 最新

  • duanliao6077 2011-05-13 20:50
    关注

    Following should get you started.

    Note that the only difference is that the third period comprises 15 days io 14 according to DATEDIFF.

    SQL Statement

    ;WITH q AS (
      /* Kick of with the record where startdate < input < enddate */
      SELECT  date_start
              , date_end
      FROM    @HouseSearch
      WHERE   date_start <= @date_start
              AND date_end >= @date_start
              AND nb_people >= @nb_people -- Only when number of people is adequate
      UNION ALL
      SELECT  q.date_start
              , hs.date_end
      FROM    q
              INNER JOIN @HouseSearch hs ON hs.date_start = q.date_end
      WHERE   nb_people >= @nb_people -- Only when number of people is adequate
    )
    SELECT  *
    FROM    (
              -- Only return result if sequence exists between date range
              SELECT  date_start = MIN(date_start)
                      , date_end = MAX(date_end)
              FROM    q
              WHERE   date_end >= @date_end 
            ) datetimerange
            -- Calculate the average price
            CROSS APPLY (
              SELECT  [AveragePrice] = SUM(price / DATEDIFF(dd, @date_start, @date_end))
              FROM    (
                        -- Price for all records where date_end <= @date_end 
                        SELECT  [price] = 
                                  CASE WHEN @date_start < date_start 
                                  THEN DATEDIFF(dd, date_start, date_end) * price
                                  ELSE DATEDIFF(dd, @date_start, date_end) * price
                                  END                        
                        FROM    @HouseSearch        
                        WHERE   @date_end > date_end
                        UNION ALL
                        -- Price of remaining records where date_end >= @date_end
                        SELECT  DATEDIFF(dd, date_start, @date_end) * price
                        FROM    @HouseSearch        
                        WHERE   @date_end between date_start AND date_end
                      ) prices
            ) price                  
    WHERE   date_start IS NOT NULL            
    

    Test data

    DECLARE @HouseSearch TABLE (
      date_start DATE
      , date_end DATE
      , nb_people INTEGER
      , price FLOAT
    )  
    
    INSERT INTO @HouseSearch VALUES
      ('2011-01-01', '2011-01-25', 4, 100)
      , ('2011-01-25', '2011-02-14', 3, 120)
      , ('2011-02-14', '2011-03-12', 3, 140)
      , ('2011-03-12', '2011-04-10', 3, 100)
    
    DECLARE @date_start DATE = '2011-01-15'
    DECLARE @date_end DATE = '2011-03-01'
    DECLARE @nb_people INTEGER = 3
    DECLARE @price_low FLOAT = 90
    DECLARE @price_high FLOAT = 15
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?