如何在PHP类中“隐藏”私有变量

Question

I might not have a good understanding of this, but since the "username" variable is private. Shouldn't this not be a part of the return? How do I make it so the $username is private and not outputed, but the public member is?

class MyClass 
{
    private $username = "api";


    public function create_issue()
    {
        $this->public = "Joe";
        return $this;
    }

}

$test = new MyClass();
$test->create_issue();

var_dump($test);

class MyClass#1 (2) {
  private $username =>
  string(3) "api"
  public $public =>
  string(3) "Joe"
}

Answer 1

Note: Don't ever use var_dump to render your class unless it's for debugging purposes.

Even though this is not the intent of private scope, interestingly enough, you can use echo json_encode($object); and the private variables within the class will not be outputted. You can then safely use this JSON in your API.

class MyClass 
{
    private $username = "api";


    public function create_issue()
    {
        $this->public = "Joe";
        return $this;
    }

}

$test = new MyClass();
$test->create_issue();

echo json_encode($test); // prints {"public":"Joe"}

Read up more on proper private/protected/public usage here