如何在php中将值推送到数组中

Question

<?php
    $ore = "piece1 piece2 piece3 piece4 piece5 piece6";
    $user = array();
    $alotted = array();

    //splitting string ore.
    $output = preg_split( "/ ( |
) /", $ore );

    //entering even value of array output to user and odd to alotted. 
    for ($x = 0; $x < sizeof($output); $x++) 
    {
        if ($x % 2 == 0) 
        {
            array_push(user,$output[$x]); //trying to put values in array user. 

        } 
        else 
        {
                array_push(alotted,$output[$x]);//trying to put value in alotted.
        }
    } 

?>

Answer 1

First off, if this is not a typo, you forgot the $ signs on:

array_push($user,$output[$x]);
        // ^ $ 
array_push($alotted,$output[$x]);
      //   ^

Then on your regex, remove the leading and trailing space:

$output = preg_split("/( |
)/", $ore); // space or newline
                   //  ^     ^ // no spaces

Refactored into this:

$ore = "piece1 piece2 piece3 piece4 piece5 piece6";
$output = preg_split("/( |
)/", $ore );
// $output = explode(' ', $ore);
$user = $alotted = array();
for ($x = 0; $x < sizeof($output); $x++) {
    ($x % 2 == 0) ? array_push($user,$output[$x]) : array_push($alotted,$output[$x]);
} 

I don't know why you have to use a regular expression on this, explode() should suffice in this particular string example.

Code:

$ore = "piece1 piece2 piece3 piece4 piece5 piece6";
foreach(explode(' ', $ore) as $x => $piece) {
    ($x % 2 == 0) ? $user[] = $piece : $alotted[] = $piece;
}