PHP使用其他变量按名称选择变量

Question

So I have a list with variables (auto-generated), something like:

$won3 = 1;
$time3 = 4;
$won6 = 0;
$time6 = 5;
$won4 = 0;
$time4 = 5;
(...)

but with many more variables. Now I want to make a table with all the variables, so I used a for-loop, but $won1 has to be the first in the table, then $won2 etc... But how can I recall this $won1 in a for-loop? I tried:

for ($X = 0, $X < $Y, $X++){
    echo '$won'.$X;
}

but this does not do the job. Anyone knows how I can solve this?

Thanks in advance.

Answer 1

First... In for loops you can't use ,

for ($X = 0, $X < $Y, $X++){

Try this:

for ($X = 0; $X < $Y; $X++){

.

And you have to choices...

for ($X = 0; $X < $Y; $X++){
    $var = 'won' . $X;
    echo $$var;

    echo ${'won' . $X};
}